Posted by mikee on Friday, January 4, 2013 at 9:05am.
How about trying these yourself, I gave you a previous solution.
They look like straight-forward right-angled triangle trig problems.
1)
Draw a diagram. The shortest distance is the perpendicular from the road to the gas station
d = 100 sin75° = 96.59 m
2)
The height of the taller building above the shorter is
h = 60 tan40° = 50.34 m
3)
The distance to the shorter building is
50 cos30° = 43.3 m
The distance to the taller building is 50 cos40° = 38.3 m
Note that there is still osme figuring to do on #2 and #3.
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