Friday

December 19, 2014

December 19, 2014

Posted by **Kelli** on Friday, January 4, 2013 at 7:52am.

f(x)=x^4+2x^3-7x^2-8x+12

x=

f(x)=

- math -
**Reiny**, Friday, January 4, 2013 at 8:48amtry factors of 12

on the first try, I got f(1) = 0

so x-1 is a factor

by long algebraic or by synthetic division , I got

x^4+2x^3-7x^2-8x+12

= (x-1)(x^3 + 3x^2 - 4x - 12)

grouping the x^3 + 3x^2 - 4x - 12

= x^2(x+3) - 4(x+3)

= (x+3)(x^2-4)

= (x+3)(x+2)(x-2)

so

x^4+2x^3-7x^2-8x+12

= (x-1)(x-2)(x+2)(x+3)

(had I been patient, I would have found

f(2) = 0, f(-3)=0 and f(-2) = 0 as well)

the zeros are

1, 2, -2, -3

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