Posted by yohannes on Friday, January 4, 2013 at 3:09am.
The radius of sphere at therate of 4cm per second .at what ratis its surface area chang when theradius is 6cm

physics  drwls, Friday, January 4, 2013 at 5:56am
You seem to have left out some words in your question, such as:
The radius of sphere IS INCREASING at the rate of 4cm per second.
Surface area is
A= 4*pi*R^2
The rate of increase of surface area is
dA/dt = 8*pi*R*(dR/dt)
Plug in 6 cm for R, and dR/dt = 4 cm/s, and compute

physics  Elena, Friday, January 4, 2013 at 6:01am
R=4t (cm)
6=4t
t=1.5 s.
A=4πR²=4π(4t)²=
=64πt²=64π(1.5)²=452.4 cm²

physics  Elena, Friday, January 4, 2013 at 6:06am
dA/dt = 64πt²=128 πt=128 π•1.5=603.2 cm²/s
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