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March 1, 2015

March 1, 2015

Posted by **Austin** on Thursday, January 3, 2013 at 11:52pm.

1/8[3 In(x+5)-In x-In(x^2-4)]

Please show work

- math -
**Reiny**, Friday, January 4, 2013 at 12:30am1/8[3 In(x+5)-In x-In(x^2-4)]

= (1/8) [ ln (x+5)^3 - lnx - ln (x^2-4) ]

= (1/8) ln ( (x+5)^3 / (x(x^2 - 4) ]

you finish it

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