Posted by Austin on Thursday, January 3, 2013 at 11:52pm.
1/8[3 In(x+5)-In x-In(x^2-4)]
= (1/8) [ ln (x+5)^3 - lnx - ln (x^2-4) ]
= (1/8) ln ( (x+5)^3 / (x(x^2 - 4) ]
you finish it
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