Posted by **Austin** on Thursday, January 3, 2013 at 11:05pm.

Solve the following equation.

log4(x+2)=lo4^7

Both of the 4's should be dropped down.

- math -
**Reiny**, Thursday, January 3, 2013 at 11:19pm
did you mean

log_{4} (x+2) = log_{4}(x^7)

or

log_{4}(x+2) = (log_{4}x)^7

or

....

your right side of the equation makes no sense

- math -
**Austin**, Thursday, January 3, 2013 at 11:31pm
log lower 4(x+2)=log lower 4 7. does this make sense know? How do you make the lower sign to be able to get the 4 lower??

- math -
**Reiny**, Thursday, January 3, 2013 at 11:41pm
I wasn't worried about the lower case, I questioned the

log4^7

it makes no sense

that is similar to something like

√^7 or tan ^7

you take the log "of something" you can't just have have log

I had guessed that there would be an x of sorts, since the left side contained the variable x

- math -
**Austin**, Friday, January 4, 2013 at 12:08am
it is written as you have it written the first time. I couldn't make out the question. It made no sense to me.

- math -
**Reiny**, Friday, January 4, 2013 at 12:24am
ok, if it is

log4 (x+2) = log4(x^7)

then x+2 = x^7 , (I "un-logged it)

x^7 = x+2 is a very nasty equation to solve, which is way beyond the scope of these kind of posts

You could use something like Newtons method

let y = x^7 - x - 2

dy/dx = 7x^6 - 1

new x = x - (x^7 - x - 2)/(7x^6 - 1)

pick any reasonable value for x

say x = 1 , (I know it does not work)

newx = 1 - (1-1-2)/(7-1)

= 1 - (-2/6) = 1.333333

make that your next x, and using a calculator

new x = 1.3333 - (....

= 1.22485...

...

newx = 1.1846

newx = 1.17975..

newx = 1.179693902

newx = 1.179693891

newx = 1.17969389 , wow, isn't that amazing

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