Posted by erika on Thursday, January 3, 2013 at 10:55pm.
I will assume you meant
x = -1 , (the + and + are on the same key)
x^2 + 3y^2 = 13
2x + 6y dy/dx = 0
dy/dx = -2x/6y = -x/3y
when x = -1 ......
1 + 3y^2 = 13
3y^2 = 12
y^2 = 4
y = ± 2
the two points are (-1,2) and (-1, -2)
at (-1,2) , slope = 1/6
at (-1,-2) , slope = 1/-6 = -1/6
2. your call
3. x^2 + xy + y^2 = 3
2x + xdy/dx + y + 2ydy/dx = 0
dy/dx(x + 2y) = -2x - y
dy/dx = (-2x - y)/(x+2y)
at (-1,2) , slope= (2-2)/(-1+4) = 0
at (-1,-1) , slope = (2+1)/(-1-2) = -1
I don't get the instructions.
" If your method fails, that’s fine, just explain thoroughly why it failed." ---- > very odd!
Thank you! helped a lot and yes I meant '=' ,
basically I think he just wants us to explain on why it did or didn't fail, yes I know very strange! :)
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