Algebra
posted by Dakota .
the length of a rectangle is 7 cm more than its width. find the demensions of the rectangle if its perimeter is 50 cm.

L=w+7
permiter=50=2L+2W=2(w+7)+2W=4W+14
4W=36
solve for W, then L
posted by Dakota .
the length of a rectangle is 7 cm more than its width. find the demensions of the rectangle if its perimeter is 50 cm.
L=w+7
permiter=50=2L+2W=2(w+7)+2W=4W+14
4W=36
solve for W, then L