Posted by faizel on Thursday, January 3, 2013 at 8:59am.
Midpoints of the sides AB and AC of a triangle ABC are ( 3 , 5 ) and ( 3 , 3 ) respectively,then the length of the side BC is

maths  Steve, Thursday, January 3, 2013 at 9:47am
let A = (h,k). Then
B=(h+2(3h),k+2(5k))=(6h,10k)
C=(h+2(3h),k+2(3,k))=(6h,6k)
BC^2 = 12^2+16^2 = 340
BC=√340
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