Posted by faizel on Thursday, January 3, 2013 at 8:59am.
let A = (h,k). Then
B=(h+2(3-h),k+2(5-k))=(6-h,10-k)
C=(h+2(-3-h),k+2(-3,k))=(-6-h,-6-k)
BC^2 = 12^2+16^2 = 340
BC=√340
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