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January 25, 2015

January 25, 2015

Posted by **waqas** on Thursday, January 3, 2013 at 6:23am.

(3y-7x-3)dx+(7y-3x-7)dy=0

- calculus -
**Steve**, Thursday, January 3, 2013 at 10:10amrearrange things a it to get

(3y-7x-3)+(7y-3x-7)y'=0

now integrate term by term

3xy-7/2x^2-3x + 7/2y^2-3xy-7y=0

the 3xy's go away; multiply by 2/7 to get

-(x^2+6/7)+(y^2-2y) = 0

-(x+3/7)^2+(y-1)^2 = 58/49

an hyperbola opening up and down

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