Thursday

July 31, 2014

July 31, 2014

Posted by **waqas** on Thursday, January 3, 2013 at 6:23am.

(3y-7x-3)dx+(7y-3x-7)dy=0

- calculus -
**Steve**, Thursday, January 3, 2013 at 10:10amrearrange things a it to get

(3y-7x-3)+(7y-3x-7)y'=0

now integrate term by term

3xy-7/2x^2-3x + 7/2y^2-3xy-7y=0

the 3xy's go away; multiply by 2/7 to get

-(x^2+6/7)+(y^2-2y) = 0

-(x+3/7)^2+(y-1)^2 = 58/49

an hyperbola opening up and down

**Related Questions**

Integral calculus - Please do help solve the followings 1) Integrate e^4 dx 2) ...

calculus 2 - Justify, with a written explanation or a mathematical reasoning ...

calculus - 1) Integrate Cos^n(x) dx 2) Integrate e^(ax)Sinbx dx 3) Integrate (...

Calculus - 6.] Replace the integral in exercise 5 (int. (1/ 1 – t) dt a = 0, b...

Calculus AB - Please help me integrate this equation using partial fractions: ...

Calculus - How do you integrate [(x^2)(cos(2(x^3)))]? I tried to integrate by ...

calculus help please - dy/dx = 2y^2 Integrating...y=2/3 y^3 + C put 1,-1 into ...

Calculus - Integrate the following (x^5 - 2)dx

Integral calculus - Please can anyone help with the following problems - thanks...

calculus - 1) Integrate (e^x+x)^2(e^x+1) dx 2) Integrate xe^x2 dx Let u=(e^x+x) ...