Posted by **Zia** on Thursday, January 3, 2013 at 4:43am.

Find the area of the indicated region. We suggest you graph the curves to check whether one is above the other or whether they cross, and that you use technology to check your answer. (Round your answer to four decimal places.)

Enclosed by y = ln x, y = 2 − ln x, and x = 4

- Business Math -
**Reiny**, Thursday, January 3, 2013 at 9:21am
you will need the intersection of

y = lnx and y = 2-lnx

2lnx= 2

lnx = 1

x = e

so you will have a region shaped like an "arrow head" from x=e to 4

Area = ∫(2 - 2lnx) dx from x = e to 4

(remember the integral of lnx is

xlnx - x , which should be in your repertoire of common integrals )

= [-2xlnx + 4x] from e to 4

= -8ln4 + 16 - (-2e + 4e)

= .....

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