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August 2, 2014

August 2, 2014

Posted by **Zia** on Thursday, January 3, 2013 at 4:43am.

Enclosed by y = ln x, y = 2 − ln x, and x = 4

- Business Math -
**Reiny**, Thursday, January 3, 2013 at 9:21amyou will need the intersection of

y = lnx and y = 2-lnx

2lnx= 2

lnx = 1

x = e

so you will have a region shaped like an "arrow head" from x=e to 4

Area = ∫(2 - 2lnx) dx from x = e to 4

(remember the integral of lnx is

xlnx - x , which should be in your repertoire of common integrals )

= [-2xlnx + 4x] from e to 4

= -8ln4 + 16 - (-2e + 4e)

= .....

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