Sunday
November 23, 2014

Homework Help: AP CHEMISTRY

Posted by Amber on Wednesday, January 2, 2013 at 9:51pm.

What is the of a solution obtained by dissolving two extra-strength aspirin tablets, containing 594 of acetylsalicylic acid each, in 202 of water?

The active ingredient in aspirin is acetylsalicylic acid , a monoprotic acid with Ka=3.3*10^-4 at 25 C.

Can you provide the method, for some reason I keep getting the answer wrong.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

chemistry - Acetylsalicyclic Acid, HC9H704, is the active component is aspirin. ...
Chemistry - 18) Aspirin is a monoprotic acid called acetylsalicylic acid. Its ...
Chemistry - Aspirin is a weak acid with a Ka of 3.0x10^-5. Find the pH of a ...
Chemistry - Acetylsalicylic acid (C9H8O4) is a monoprotic acid commonly known as...
Chemistry - Aspirin equilibrium is : HC9H7O4(aq) + H2O (double arrow)C9H7O4^-(aq...
Chemistry - 1. Calculate the acetylsalicylic acid concentration (in mg/mL) of ...
chem - quantitative determination of acetylsalicylic acid in aspirin tablets by ...
Chemistry - Aspirin can be prepared by the reaction of salicylic acid with an ...
chemistry - aspirin tablets contain about 5 grains of aspirin. About 10 grams of...
Chem - Aspirin (acetylsalicylic acid, ) is a weak monoprotic acid. To determine ...

Search
Members