Posted by **Nina** on Wednesday, January 2, 2013 at 6:00pm.

(h)t=-4.9t^2+98t+8 Find the max height?

- math -
**Reiny**, Wednesday, January 2, 2013 at 6:21pm
are you taking Calculus ?

then

h'(t) = -9.8t + 98 = 0

t = 10

h(10) = -4.9(100) + 98(10) + 8 = 498

or

complete the square

h(t) = -4.9(t^2 - 20t + **100 - 100**) + 8

= -4.9( (t-10)^2 - 100) + 8

= -4.9(T-10)^2 + 490+8

= -4.9(t-10)^2 +498

vertex is (10, 498) , so max height is 498

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