Posted by Nina on .
(h)t=4.9t^2+98t+8 Find the max height?

math 
Reiny,
are you taking Calculus ?
then
h'(t) = 9.8t + 98 = 0
t = 10
h(10) = 4.9(100) + 98(10) + 8 = 498
or
complete the square
h(t) = 4.9(t^2  20t + 100  100) + 8
= 4.9( (t10)^2  100) + 8
= 4.9(T10)^2 + 490+8
= 4.9(t10)^2 +498
vertex is (10, 498) , so max height is 498