posted by Jim on .
Two jets are traveling toward each other and are 4000km apart. The rate of one jet is 100km/h faster than the rate of the other. If the jets pass each other after 2.5 hours, what is the rate of the faster jet?
rate of slower jet ---- x km/h
rate of faster jet ----- x+100 km/h
solve for x
2.5x+ 2.5(x+100) = 4000
(I got x = 750 , so the faster jet goes 850 km/h)