Posted by **Kate** on Wednesday, January 2, 2013 at 5:14pm.

Steve McSpoke left home on his bicycle at 8am, traveling at 18km/h. At 10am, Steve's brother set out after him on a motorcycle, following the same route. The motorcycle traveled at 54km/h. How long had steve traveled when his brother overtook him?

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**Reiny**, Wednesday, January 2, 2013 at 5:21pm
Steve's brother time to catch-up --- t hrs

Steve's time to catch-up by brother -- t+2

54t = 18(t+2)

54t = 18t + 36

36t = 36

t = 1

Steve had biked for 3 hours, when his brother overtook him.

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**Kate**, Wednesday, January 2, 2013 at 5:26pm
thanks

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**Kate**, Wednesday, January 2, 2013 at 5:27pm
Also, how far had steve traveled when his brother overtook him?

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**Reiny**, Wednesday, January 2, 2013 at 5:38pm
simply sub in the value of t = 1 into both distances., you will obviously get the same answer since they both went the same distance.

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**Kate**, Wednesday, January 2, 2013 at 5:39pm
ok

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**Kate**, Wednesday, January 2, 2013 at 5:53pm
Reiny, how can you show me how to do the last part wirten out?

Thank you so much!

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**Kate**, Wednesday, January 2, 2013 at 5:56pm
neverminds. I got it.

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