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October 21, 2014

October 21, 2014

Posted by **lg** on Wednesday, January 2, 2013 at 4:48pm.

- Functions 11: Series and Sequence 2 -
**MathMate**, Wednesday, January 2, 2013 at 4:54pmLet the four terms be a,b,c,d, and be the common ratio.

b=ar

c=ar²

d=ar³

a+b=a(1+r)=3

c+d=ar²(1+r)=4/3

(c+d)/(a+b) = r² = (4/3)/3=4/9

=>

r=√(4/9)=±2/3, assume 2/3

a+b=a(1+r)=a(1+2/3)=5a/3=3

=>

a=9/5

b=ar=6/5

c=ar²=4/5

d=ar³=8/15

- Functions 11: Series and Sequence 2 -
**lg**, Wednesday, January 2, 2013 at 5:07pmThanks a lot:)

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