Posted by **lg** on Wednesday, January 2, 2013 at 4:48pm.

The sum of the first two terms of a geometric sequence is 3. The sum of the next two terms is 4/3. Find the first four terms of the sequence.

- Functions 11: Series and Sequence 2 -
**MathMate**, Wednesday, January 2, 2013 at 4:54pm
Let the four terms be a,b,c,d, and be the common ratio.

b=ar

c=ar²

d=ar³

a+b=a(1+r)=3

c+d=ar²(1+r)=4/3

(c+d)/(a+b) = r² = (4/3)/3=4/9

=>

r=√(4/9)=±2/3, assume 2/3

a+b=a(1+r)=a(1+2/3)=5a/3=3

=>

a=9/5

b=ar=6/5

c=ar²=4/5

d=ar³=8/15

- Functions 11: Series and Sequence 2 -
**lg**, Wednesday, January 2, 2013 at 5:07pm
Thanks a lot:)

## Answer This Question

## Related Questions

- math - in an arithmetic sequence the common difference is equal to 2.the first ...
- Advanced Functions - I need help answering these questions 1. State the Common ...
- Maths - 1..The first 2 terms of a geometric progression are the same as the ...
- Math *URGENT - Please give the answers and solutions for each. 1.If the second ...
- Further mathematics - An exponential sequence (GP)of positive terms and a linear...
- math - The first and second terms of an exponential sequence (G.P) are ...
- Further mathematics - An exponential sequence of positive terms and a linear ...
- Math 12 - the sum of the first 2 terms of a geometric sequence is 3. the sum of...
- Can someone help me?! - The 1st, 5th and 13th terms of an arithmetic sequence ...
- Algebra II - The first 3 terms in a geometric sequence are 1.1, 1.65, and 2.475...

More Related Questions