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February 27, 2015

February 27, 2015

Posted by **Marika** on Wednesday, January 2, 2013 at 4:20pm.

- Trigonometry -
**Reiny**, Wednesday, January 2, 2013 at 5:10pmI made a side view diagram, with A and B the points on the lake, obviously A farther away from the tower. I labeled my tower DC , C as the base of the tower.

In Triangle ABD, angle A = 7°, angle ABD = 167° , angle ADB = 6° , and AB = 1 km

by the sine law:

BD/sin7 = 1/sin6

BD = sin7/sin6 = 1.16589... (keep number in calculator's memory)

Now in the right-angled triangle, BCD

DC/BD = sin13

DC = 1.16589..(sin13) = .26226 km

or appr 226 m

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