Posted by **rajeev** on Wednesday, January 2, 2013 at 11:12am.

find the equation of a straight line on which the perpendicular from the origin makes an angle of 30 degree with the x-axis and which forms a triangle of are 50/root3 with the axes

- maths -
**Steve**, Wednesday, January 2, 2013 at 11:25am
if the base has length x,

area = 1/2 * x * x√3 = √3/2 x^2 = 50/√3

x = 10

so, y = 10√3

so, the line is

x/10 + y/(10√3) = 1

- maths -
**Steve**, Wednesday, January 2, 2013 at 11:26am
oops. x = 10/√3

y = 10

x/(10√3) + y/10 = 1

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