Posted by **Anonymous** on Wednesday, January 2, 2013 at 8:55am.

the inside perimeter of a running track shown in figure is 400m the lenghth of each of the straight portion is 90, and the ends are semicircles, if the track is 14 m wide everywherwe,find the area of the track. also find the length of thee outerboundary of the track

- maths -
**Steve**, Wednesday, January 2, 2013 at 10:53am
inside length:

400 = 90*2 + 2*pi*r

r = 110/pi

outside length: 90*2 + 2*pi*(r+14) = 400+28pi = 487.96

area of track is 2*90*14 + pi(R^2-r^2)

= 2520 + pi((110/pi+14)^2 - (110/pi)^2)

= 5600+196pi

= 6215.75 m^2

- maths -
**satish**, Sunday, December 11, 2016 at 3:21am
First area ofrunning small rectangle =l×b secon step area oftwo small semi-circle =one complete circle-area of two small circle . Then large circle-area of small circle. Thenarea of large circle+rectangle

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