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February 26, 2015

February 26, 2015

Posted by **Anonymous** on Wednesday, January 2, 2013 at 8:55am.

- maths -
**Steve**, Wednesday, January 2, 2013 at 10:53aminside length:

400 = 90*2 + 2*pi*r

r = 110/pi

outside length: 90*2 + 2*pi*(r+14) = 400+28pi = 487.96

area of track is 2*90*14 + pi(R^2-r^2)

= 2520 + pi((110/pi+14)^2 - (110/pi)^2)

= 5600+196pi

= 6215.75 m^2

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