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April 20, 2014

April 20, 2014

Posted by **Ashok** on Tuesday, January 1, 2013 at 9:03pm.

a.) HCl from "concentrated" (12M) reagent.

b.) Sodium Carbonate from the pure solid

PLEASE SO LOST(explanation of why you did of what woulp help so much) Thank You

- science -
**Steve**, Wednesday, January 2, 2013 at 11:00ama)

since the concentration is reduced by a factor 24, use 1/24 L of concentrated acid and add 23/24 L of water.

b)

1L of .5M contains .5 moles of Na2CO3. So, put 53g Na2CO3 in a beaker and fill with water to 1.00L of volume

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