Posted by Ashok on .
Describe and show your calculations on how you would prepare 1.00L of a 0.50M solution of each of the following
a.) HCl from "concentrated" (12M) reagent.
b.) Sodium Carbonate from the pure solid
PLEASE SO LOST(explanation of why you did of what woulp help so much) Thank You
since the concentration is reduced by a factor 24, use 1/24 L of concentrated acid and add 23/24 L of water.
1L of .5M contains .5 moles of Na2CO3. So, put 53g Na2CO3 in a beaker and fill with water to 1.00L of volume