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December 19, 2014

December 19, 2014

Posted by **Heather** on Tuesday, January 1, 2013 at 6:30pm.

f(x)=x^2+x^2-8

a. what is the vertex (h,k) of f?

(h,k)=? simplify your answer and type the answer in an ordered pair

b. what is the axis of symmetry?

- math -
**Riana**, Tuesday, January 1, 2013 at 6:37pma. (0,-8) is the vertex

- math -
**Riana**, Tuesday, January 1, 2013 at 6:42pmb. axis of symmetry is zero.

- check - math -
**Reiny**, Tuesday, January 1, 2013 at 7:24pmI have a feeling there is a typo.

Why would anybody have two like terms in the equation ?

should it be

f(x) = x^2 + 2x - 8 ????

- math -
**Heather**, Tuesday, January 1, 2013 at 7:38pmYes, Reiny you caught the typo

It should read f(x)=x^2+2x-8, thank you for catching that. So, now my answers will change that Riana gave. Right?

- math -
**Reiny**, Tuesday, January 1, 2013 at 7:43pmyes,

complete the square ....

f(x) = x^2 + 2x**+1 - 1**-8

= (x+1)^2 - 9

vertex is (-1,-9)

axis of symmetry: x = -1 or x+1 = 0

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**Riana**, Tuesday, January 1, 2013 at 7:46pmthen your vertex is (-2,8)

and axis will be -1

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**Riana**, Tuesday, January 1, 2013 at 7:47pmthe vertex can't be (-1,-9) its incorrect.

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**Reiny**, Tuesday, January 1, 2013 at 7:48pmNO, check my reply

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**Reiny**, Tuesday, January 1, 2013 at 7:52pmYes it is !

http://www.wolframalpha.com/input/?i=plot+x%5E2+%2B+2x+-+8

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