Monday

October 20, 2014

October 20, 2014

Posted by **Leasha** on Tuesday, January 1, 2013 at 12:38pm.

I tried, and for the first derivative I got -1/(2*sqrt((1-x^2)^3)). I then found critical values of the function to be -1 and 1.

However, the textbook says that the minimum value is 1 at f(0), and I have absolutely no idea where they came up with that answer... Help please!

- Calculus -
**David Q/R**, Tuesday, January 1, 2013 at 3:47pmI think there's posibly a piece of information missing in the question as you've stated it, which is that you're only supposed to be looking at the function between the values X = -1 and X = +1, because the function is discontinuous at both of those values, and also takes smaller values than f(X) = 1 outside that range: try X = -2 or +2, and you'll get f(X) = -1/3, which is certainly less than 1.

Secondly, I think you've got the differentiation wrong: I get df/dx = 2x/(1-x^2)^2, which if you set it to zero gives you just one real turning point at x = 0, for which f(x) = 1 as stated in the textbook.

**Answer this Question**

**Related Questions**

Calculus - another question - "Find the absolute minimum value of the function f...

Calculus - For y=(1/4)x^4-(2/3)x^3+(1/2)x^2-3, find the exact intervals on which...

Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...

Calculus - For f(x)=2(x+5)^3 +7 Find and classify the extreme values, determine ...

Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...

Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...

extreme value of absolute..... - find the extreme values of the function on the ...

increasing decreasing and more - How to analytically find the intervals on which...

calculus - Find the length of the arc formed by y = (1/8)(4x^2-2ln(x)) from x=4 ...

Calc I - Find the range of y = (3x-1)/(2x^2 + x - 6) I was going to take the ...