Sunday
January 25, 2015

Homework Help: Calculus

Posted by Leasha on Tuesday, January 1, 2013 at 12:38pm.

Find the extreme value(s) of the function f(x)=1/(1-x^2).

I tried, and for the first derivative I got -1/(2*sqrt((1-x^2)^3)). I then found critical values of the function to be -1 and 1.
However, the textbook says that the minimum value is 1 at f(0), and I have absolutely no idea where they came up with that answer... Help please!

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Please check my Calculus - 1. Find all critical values for f(x)=(9-x^2)^⅗ ...
Please check my Calculus - 1. Which of the following describes the behavior of f...
Please check my Calculus - 1. Find all points of inflection of the function f(x...
Please check my Calculus - 1. Find all points of inflection of the function f(x...
Calculus - another question - "Find the absolute minimum value of the function f...
Calculus - For y=(1/4)x^4-(2/3)x^3+(1/2)x^2-3, find the exact intervals on which...
Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...
Calculus - For f(x)=2(x+5)^3 +7 Find and classify the extreme values, determine ...
Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...
Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...

Members