Posted by **NayNay** on Tuesday, January 1, 2013 at 10:18am.

solve the logarithmic equation. Be sure to reject any value of x that is not in the domain.

In square root x+7=1

x= ?

What is the decimal approximation to the solution?

x= ?

- calculus -
**Knights**, Tuesday, January 1, 2013 at 10:29am
so sqrt { x+7} = 1 right?

if so... then square both sides to get x+7 =1

x = -6

- calculus -
**Reiny**, Tuesday, January 1, 2013 at 10:41am
I think Knights missed the "ln" in front

ln √(x+7) = 1

√(x+7) = e^1 = e

square both sides

x+7 = e^2

x = e^2 - 7

x = appr .389

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