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solve the logarithmic equation. Be sure to reject any value of x that is not in the domain.

In square root x+7=1
x= ?

What is the decimal approximation to the solution?
x= ?

  • calculus -

    so sqrt { x+7} = 1 right?

    if so... then square both sides to get x+7 =1
    x = -6

  • calculus -

    I think Knights missed the "ln" in front

    ln √(x+7) = 1
    √(x+7) = e^1 = e
    square both sides
    x+7 = e^2

    x = e^2 - 7
    x = appr .389

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