solve the following logarithmic equation. Be sure to reject any value of x that is not in the domain of orginal expression. then in the solution set round to two decimals places.

Inx=8
I get e^8

But am having a hard time with rounding two decimal places. Can someone help?

e^8 is correct.

you're in calculus, and can't round a number? Fie on thee!

e^8 = 2980.957987 = 2980.96

To solve the logarithmic equation ln(x) = 8, you'll first need to isolate the variable x. In this case, because the logarithm base is e (the base of natural logarithms), the inverse function of ln(x) is e^x. This gives us the equation e^x = e^8.

To find the value of x, you can take the natural logarithm (ln) of both sides of the equation to cancel out the exponential function. So, ln(e^x) = ln(e^8). Since ln and e^ are inverse functions, ln(e^x) simplifies to x, and ln(e^8) simplifies to 8. Therefore, x = 8.

Now, regarding rounding to two decimal places, the given solution x = 8 doesn't require rounding since it is already an integer. However, if you need to round a solution to two decimal places, consider the following example:

If the solution was x = 3.145926, to round to two decimal places, you would keep the first two numbers after the decimal point, which gives x ≈ 3.15.

Remember that rounding is necessary only when the result is not already rounded or you specifically need to round it for a particular purpose.