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December 17, 2014

December 17, 2014

Posted by **algebra** on Monday, December 31, 2012 at 3:20pm.

- math -
**Steve**, Tuesday, January 1, 2013 at 12:04amv = ∫[0,a] π(R^2-r^2) dx

= π∫[0,a] (2x)^2 - (x^2)^2 dx

= πa^3(4/3-a^2/5)

so, we want πa^3(4/3-a^2/5) = 7/12 π a^3

4/3 - a^2/5 = 7/12

80 - 12a^2 = 35

12a^2 = 55

a = √(55/12)

- math -
**Steve**, Tuesday, January 1, 2013 at 12:05amoops: √45/12 = √(15/2)

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