Posted by Julienne on Monday, December 31, 2012 at 2:07pm.
original:
y = ln(x+1) + 1
inverse:
x = ln(y+1) + 1
x-1 = ln(y+1)
solving for y ....
y+1 = e^(x-1)
y = e^(x-1) - 1
or
f^-1 (x) = e^(x-1) - 1
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