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January 20, 2017
Posted by **nathalie** on Monday, December 31, 2012 at 12:10pm.

x^5-3x^4-24x^3-72x^2-25x+75=0

5x^5-20x^4-40x^3-16x^2-45x+180=0

-3x^5+3x^4+9x^3-7x^2+12x=12

x^3-x^2-13x-13=0

x^3+x^2=15x-15

Thank you for any help...I'm desperate please help :(

- algebra 2 -
**TutorCat**, Monday, December 31, 2012 at 5:47pmFor the first three, you would have to apply the rational zero theorem ((Broken Link Removed) and then use synthetic division ((Broken Link Removed) to see if the remainder is zero.

For the last two, you would group the terms and factor out a common factor method(http://www.chesapeake.edu/khennayake/MAT113/3.2Solution.htm). - algebra 2 -
**Henry**, Monday, December 31, 2012 at 8:58pmThis was done by trial and error assisted by EXCEL. Very tedious!

1.Solution Set: X =-1.5887,0.7772,-1.2089, and 0.8717.

2.X = -2.07316,1.2139,-5.0432, and 2.2307.

3. X = -1.9548,2.1191, and 0.9050.

4. X = -2.218,4.516,-11.908,-1.0917.

5. x^3+x^2 = 15x-15.

x^3+x^2-15x+15 = 0.

NOTE: All values of X shown are called

ZEROES, because they give zero output

when plugged into the Eq.

I hope I've helped.

X = -2.218,1.220,13.923,1.0774.