Posted by **John** on Monday, December 31, 2012 at 10:23am.

identify the vertex, axis of symmetry and the dirction of opening for y=-(x-6)^2-5

- algebra 2 -
**Sarah**, Monday, December 31, 2012 at 10:30am
vertex(6,-5)

Direction is opening down(maximum)

I don't know the axis of symmetry...but I hope this helped:)

- algebra 2 -
**drwls**, Monday, December 31, 2012 at 10:32am
Vertex at x = 6, y = -5. That is the largest possible value of y along the curve.

Axis of symmetry is x = 6 vertical line.

Direction of the parabola's opening is down

- algebra 2 -
**Sarah**, Monday, December 31, 2012 at 10:35am
Oh wait for the axis of symmetry put the vertex form to standard form and then do

-b/2a

For example:

x^2+6x+13 A=1 B=6 C=13

Axis of Symmetry equation x=-b/2a

x=-6/2(1)

x=-3

- algebra 2 -
**Damon**, Monday, December 31, 2012 at 10:58am
Sarah,

(x-6)^2 is the same both sides of x = 6. For this problem you do not need

[-b +/- sqrt(b^2-4ac) / 2a

- algebra 2 -
**Sarah**, Monday, December 31, 2012 at 12:24pm
ok well sorry:P

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