posted by John .
identify the vertex, axis of symmetry and the dirction of opening for y=-(x-6)^2-5
Direction is opening down(maximum)
I don't know the axis of symmetry...but I hope this helped:)
Vertex at x = 6, y = -5. That is the largest possible value of y along the curve.
Axis of symmetry is x = 6 vertical line.
Direction of the parabola's opening is down
Oh wait for the axis of symmetry put the vertex form to standard form and then do
x^2+6x+13 A=1 B=6 C=13
Axis of Symmetry equation x=-b/2a
(x-6)^2 is the same both sides of x = 6. For this problem you do not need
[-b +/- sqrt(b^2-4ac) / 2a
ok well sorry:P