Posted by Daniel on Sunday, December 30, 2012 at 9:54pm.
43/√2 = 30.4, so the wind's vector is (-30.4,-30.4)
If the plane flies on heading θ,
(-30.4,-30.4)+(430cos(θ-45°),430sin(θ-45°)) = (0,y)
so, we have -30.4 + 430cos(θ-45) = 0
cos(θ-45) = 30.4/430 = 4.05
so, the plane flies N41°E
is 41 degrees east of north the exact degree number??? because a computer program wants the exact number and i cant round over or under 1%...
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