Posted by **Daniel** on Sunday, December 30, 2012 at 9:54pm.

An airplane ﬂies at airspeed (relative to the air) of 430 km/h . The pilot wishes to ﬂy due North (relative to the ground) but there is a 43 km/h wind blowing Southwest (direction 225◦).

In what direction should the pilot head the plane (measured clockwise from North)?

Answer in units of degrees.

- Physics -
**Steve**, Monday, December 31, 2012 at 12:05am
43/√2 = 30.4, so the wind's vector is (-30.4,-30.4)

If the plane flies on heading θ,

(-30.4,-30.4)+(430cos(θ-45°),430sin(θ-45°)) = (0,y)

so, we have -30.4 + 430cos(θ-45) = 0

cos(θ-45) = 30.4/430 = 4.05

so, the plane flies N41°E

- Physics -
**Daniel**, Monday, December 31, 2012 at 4:17am
is 41 degrees east of north the exact degree number??? because a computer program wants the exact number and i cant round over or under 1%...

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