Posted by Katie on Sunday, December 30, 2012 at 5:23pm.
dv = e^3x
v = (1/3)e^3x !!!!!!
Okay then, is this the final answer
= (5-x)(3e^3x) + (integral) -- (1/3)e^3x
= (5-x)(3e^3x) + (1/9)e^3x + C
No. You are using the wrong v function in the u*v term. See Damon's answer.
The (Integral)-v*du term is:
-(Integral)(1/3)e^3x(-dx)
= (1/9)e^3x
So your answer is ok for that term
ok, thank you very much. Happy New Year
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