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August 30, 2014

August 30, 2014

Posted by **Blake** on Sunday, December 30, 2012 at 2:13pm.

Distance, x: (14) (24) (41) (55)

Height, y: (86.43) (91.36) (92.19) (85.75)

Write the equation that best fits the path of the rock from Jesse to the lake below.

I wasn't at school when we were taught this and the notes I have mention nothing of this. I am completely lost, can someone help?

- Math -
**Reiny**, Sunday, December 30, 2012 at 5:49pmI will assume you want your data to fit an equation of the type

y = ax^2 + bx + c

from the first "point" (14,86.43)

86.43 = 196a + 14b + c , (#1)

from the 2nd:

91.36 = 576a + 24b + c , (#2)

from the 3rd:

92.19 = 1681a + 41b + c , (#3)

#2 - #1:

4.93 = 380a + 10b -----#4

#3 - #2

.83 = 1105a + 17b ---- #5

#4 times 17 -----> 83.81 = 6460a + 170b

#5 times 10 -----> 8.3 = 11050a + 170b

subtract them

-75.51 = 4590a

a = -.01645

in #4:

4.93 = 380(-.01645) + 10b

b = 1.11814

in #1

86.43 = 196(-.01645) + 14(1.11814) + c

c = 74**y = -.1645x^2 + 1.11814x + 74**

testing for point not used:

(55,85.75)

RS = -.01645(55^2) + 1.11814(55) + 74

= 85.73

the given data was 85.74 , not bad

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