Posted by **Isha** on Sunday, December 30, 2012 at 6:42am.

Solve:

The posistion of a particle moving along a coordinate line is s=sqrt(5+4t), with s in meters and t in seconds.

Find the particle's velocity at t=1 sec.

A) 2/3 m/sec

B) 4/3 m/sec

C) -1/3 m/sec

D) 1/6 m/sec

Thank you!

- Calculus -
**drwls**, Sunday, December 30, 2012 at 7:33am
Differentiate s(t). The derivative, ds/dt, is the speed as a function of t.

ds/dt = [(1/2)/sqrt(5 +4t)]*4

= 2/sqrt(5+4t)

At t = 1, this equals 2/(sqrt9) = 2/3

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