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September 1, 2014

September 1, 2014

Posted by **Breanna** on Sunday, December 30, 2012 at 5:21am.

degree 4, zeros 3, multiplicity 2; 6i

f(x)=a()

Can someone show how to do this. I have tried and do not have a clue. I am lost!!! So, please show work.

- calculus -
**Steve**, Sunday, December 30, 2012 at 6:00amby the time you get to calculus, you should know how to use the roots to form a polynomial. If you tried, you should show what you have tried, and where you got stuck.

If a is a root of f(x)=0, (x-a) is a factor of f(x).

Since complex roots come in pairs, -6i is also a root, so

f(x) = (x-3)(x-3)(x-6i)(x+6i)

= (x-3)^2 (x^2+36)

saying you do not have a clue indicates either

a) you have woefully neglected your studies, or

b) you are just lazy and want someone else to do your work, or

(c) both of the above.

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