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October 24, 2016
Posted by **Jennifer** on Sunday, December 30, 2012 at 5:12am.

1.solve the equation in the real number system. x^4+11x^3+24x^2-23x+35=0

**Please show work**

2.Use the remainder theorem to find the remainder. When f(x)is divided by x-3. Then use the factor theorem to determine whether x-3 is a factor of f(x)

f(x)=2x^4-8x^3+14x+12

the remainder is ?

is x-3 a factor of f(x)=2x^4-8x^3+14x+12

**please show work here as well. Thanks**

- calculus-can someone please help me with this ques -
**Steve**, Sunday, December 30, 2012 at 5:52am1.

you know that any rational roots will be factors of 35

a little synthetic division shows that

f(x) = (x+5)(x+7)(x^2-x+1)

the quadratic has no real roots

2.

the remainder is f(3). Naturally, if the remainder is zero, (x-3) is a factor.

f(3) = 2*81-8*27+14*3+12=0