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December 18, 2014

December 18, 2014

Posted by **Paul--please help!!** on Saturday, December 29, 2012 at 10:10pm.

This is the question.

Solve the following inequality. write your answer in interval notation.

x^3+9x^2-108 less than or equal to o

My anser:

(x+6)(x+6)(x-3)

we have double zeros at x= -6

graph comes from way low and bounces back down off the x-axis at x= -6

- calculus -
**Paul**, Saturday, December 29, 2012 at 10:16pmHere is the rest of the answer:

then dropping down negative again

then it comes back up again and goes positive and crosses the x-axis at x=3

and from then on is positive

x=3

(-00,3)u(0,6)

**Now she says note that the last term does not contain an x. What type of method did I use in this posting. Explain this method. Can someone help me please

- calculus -
**Steve**, Saturday, December 29, 2012 at 11:21pmNot sure what you're going on about.

What do you mean "type of factorization"?

I used synthetic division to come up with the roots. If you have no clue, then you need to review finding roots of a function.

The roots are where the graph touches or crosses the x-axis.

The question is:

solve f(x) <= 0

The answer is:

f(x) <= 0 when x <= 3.

In interval notation, x is in (-oo,3]

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