Posted by Samantha on Saturday, December 29, 2012 at 3:40pm.
Two cylinders have the same volume. If the radius of cylinder I is 3 times the radius of cylinder II, then the height of cylinder II is how many times the height of cylinder I?
Please explain how, if possible.
Geometry - drwls, Saturday, December 29, 2012 at 4:22pm
Cylinder 1 has nine times the base area of cylinder 2.
Volume is (base area) x (height)
For the volumes to be equal, cylinder 2 must have 9 times the height of cylinder 2.
Geometry - Henry, Saturday, December 29, 2012 at 4:35pm
pi*r^2*h2 = pi*(3r)^2*h1.
pi*r^2*h2 = pi*9r^2*h1
Divide both sides by pi*r^2:
h2 = 9*h1.
Geometry (typo correction) - drwls, Sunday, December 30, 2012 at 2:16am
For the volumes to be equal, cylinder 2 must have 9 times the height of cylinder 1
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