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March 6, 2015

March 6, 2015

Posted by **Margaret** on Saturday, December 29, 2012 at 12:57pm.

- Math -
**Steve**, Saturday, December 29, 2012 at 1:32pmIf you mean to solve

x^3+9x^2-108 <= 0

first find the factors:

(x+6)^2 (x-3) <= 0

Now, (x+6)^2 >= 0 for all x, so we want

(x-3) <= 0

x <= 3

Makes sense, since if you think of the graph, it comes up from lower left, touches the x-axis at x = -6, dips back down, and finally crosses into positive values at x=3.

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