Post a New Question

Math

posted by on .

X^3+9x^2-108¡Ý0

  • Math - ,

    If you mean to solve
    x^3+9x^2-108 <= 0
    first find the factors:
    (x+6)^2 (x-3) <= 0

    Now, (x+6)^2 >= 0 for all x, so we want
    (x-3) <= 0
    x <= 3

    Makes sense, since if you think of the graph, it comes up from lower left, touches the x-axis at x = -6, dips back down, and finally crosses into positive values at x=3.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question