Posted by Yvette B. on Friday, December 28, 2012 at 8:20pm.
If Y varies inversely as X^2, determine what Y would be if X = 2 and another point on the equation is (1,8).
The answer I got was y=1/2^2=1/4
I'm not sure I worked this out correctly, is this correct?

ALG2  bobpursley, Friday, December 28, 2012 at 8:31pm
no.
y=k/x^2 then consider the point 1,8
8=k/1^2 k=8
y=8/x^2
if x is 2, then y=2
another way to think this out: y is 8 when x is one, so if you double x, then y must be changed by 1/4, or y=2

ALG2  Yvette B., Friday, December 28, 2012 at 8:33pm
Thank you!
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