If a solution of sodium hydroxide is mixed from a 3M solution of sodium hydroxide, such that the volume of the original solution is 50ml and the volume of the final solution is 150ml, determine each of the following:

a. The volume of water added to the solution
b. The new concentration.
c. The mass of NaOH in both solutions.

you diluted it 3 times, so new concentration= .75M (you added one part orig, 2 parts water).

volume added: 100ml
Mass NaOH is the same in each.

.05*3 moles x 40g/mole

You have an easy teacher.

To determine the answers to the given questions, we will use the concept of dilution. Dilution is the process of reducing the concentration of a solution by adding more solvent (in this case, water) to it.

a. The volume of water added to the solution:
The change in volume can be calculated by subtracting the initial volume from the final volume:
Change in volume = Final volume - Initial volume
Change in volume = 150 ml - 50 ml
Change in volume = 100 ml

Therefore, 100 ml of water was added to the solution.

b. The new concentration:
To find the new concentration of the solution, we can use the formula:
C1V1 = C2V2
Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Given information:
Initial concentration (C1) = 3M
Initial volume (V1) = 50 ml
Final volume (V2) = 150 ml

Rearranging the formula to solve for C2:
C2 = (C1 * V1) / V2
C2 = (3M * 50 ml) / 150 ml

C2 = 1 M

Therefore, the new concentration of the solution is 1M.

c. The mass of NaOH in both solutions:
To determine the mass of NaOH, we need to use the formula:

Mass of a substance = Concentration (M) * Volume (L) * Molar mass (g/mol)

First, let's calculate the NaOH mass in the initial 50 ml solution:
Initial mass = (Initial concentration) * (Initial volume) * (Molar mass of NaOH)

Initial mass = (3M) * (50 ml) * (39.997 g/mol)

Initial mass = 599.955 g

Since we have diluted the solution by adding 100 ml of water, the mass of NaOH remains the same. Therefore, the mass of NaOH in both solutions is 599.955 g.