maths plse help me..
posted by Anonymous on .
how to find the cartesian eqn of plane passing through A(0,0,0) and B(3,1,2) and parellel to line (x4)/1 = (y+3)/4 = (z+1)/7
basically how to find a plane parallel to a given line??

We need two direction vectors in the plane, one is vector AB or (3, 1, 2)
the other is the direction of the line parallel to the plane which is ((1, 4, 7)
a normal to the plane would be the cross  product of the two vectors above
Assuming you know how to find that normal, I got
(1 , 19, 11)
So the plane has equation,
x  19y  11z = c
but (0,0,0) lies on it,
so
x  19y 11z = 0