Posted by Anonymous on Friday, December 28, 2012 at 11:44am.
We need two direction vectors in the plane, one is vector AB or (3, -1, 2)
the other is the direction of the line parallel to the plane which is ((1, -4, 7)
a normal to the plane would be the cross - product of the two vectors above
Assuming you know how to find that normal, I got
(1 , -19, -11)
So the plane has equation,
x - 19y - 11z = c
but (0,0,0) lies on it,
so
x - 19y -11z = 0
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