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November 28, 2014

November 28, 2014

Posted by **Anonymous** on Friday, December 28, 2012 at 6:41am.

- maths --plse help me.. -
**Reiny**, Friday, December 28, 2012 at 8:34amUse

amount = a e^(kt) where a is the initial value, k is a constant, and t is in hours

1200 = 600 e^(k(4)

2 = e^(4k)

4k = ln 2

k = ln2 /4

amount = 600 e^((ln2/4)t)

when t=8

amount = 600 e^(2ln2)

= 2400

well, duh

Since the doubling period seems to be 4 hours

in 8 hours they would have doubled twice

600 --> 1200 --> 2400

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