Posted by Anonymous on Friday, December 28, 2012 at 6:41am.
Use
amount = a e^(kt) where a is the initial value, k is a constant, and t is in hours
1200 = 600 e^(k(4)
2 = e^(4k)
4k = ln 2
k = ln2 /4
amount = 600 e^((ln2/4)t)
when t=8
amount = 600 e^(2ln2)
= 2400
well, duh
Since the doubling period seems to be 4 hours
in 8 hours they would have doubled twice
600 --> 1200 --> 2400
Related Questions
Calc - The number of bacteria in a culture is increasing according to the law of...
CALCULUS - a bacteria culture grows with a constant per capita growth rate. ...
Precalculus - NEED HELP ASAP PLEASE!! A bacteria culture starts with 2000 ...
Algebra - The number of bacteria in a certain population increases according to ...
math - The number of bacteria in a culture is modeled by: n(t) = 1330e^(0.42t) (...
algebra - neil was growin a culture of a bacteria for biology experiement. he ...
Math - he number of bacteria in a culture is modeled by n(t)=1710e071t (a) The ...
math - The number of bacteria in a culture is modeled by n(t)=1710e071t (a) The ...
algebra - neil was growing a culture of bacteria for a biology experiment. he ...
Calculus - Suppose that a population of bacteria triples every hour and starts ...
For Further Reading