Posted by Kyrstal on Thursday, December 27, 2012 at 8:09pm.
3x^2>7x-6
3 x^2 - 7 x + 6 > 0
parabola upright(holds water)
zeros at 7/6 +/- (1/6)sqrt(49-36)
7/6 +/ - (1/6)sqrt(13)
so
x< 7/6 - (1/6) sqrt 13
or
x> 7/6 + (1/6) sqrt 13
good, except it's ≤, not <
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