Posted by Austin on Thursday, December 27, 2012 at 7:15pm.
Solve the equation in the real number system
X^4+11x^3+24x^223x+35=0
Please show work

calculus  Damon, Thursday, December 27, 2012 at 7:28pm
the 35 tempts me to try 7 and 
divide mess by (x+5)
get
(x+5)(x^3+6x^26x+7)
so divide
(x^3+6x^26x+7) by (x+7)
get
(x+5)(x+7)(x^2x+1)
now that last one has no real roots
b^24ac = 14 = 3
so our only real roots are
(5,0) and (7,0)
Answer This Question
Related Questions
 calculuscan someone please help me with this ques  I have two questions if ...
 college algebraneed help please!!  solve the equation in the real number ...
 Math  Real number system  Solve the following equation in the real number ...
 Discrete Math  Please help with this problem. Thanks a/ Show that for any real ...
 college algebra  Solve the following equation in the real number system. Please...
 calculus  how to find all real zeros of "4x^5+8x^415x^323x^2+11x+15
 pre calculus  solve the following equation in the complex number system Please ...
 pre calculus  find the real zeros of f(x)=x^4+6x^311x^224x+28
 Algebra  almost done with Algebra...help! 2 3x – 6(2x – 0.055) = 10x + 0.515 I ...
 algebra  college  Solve using the elimination method. Show your work. If the ...
More Related Questions