Monday

March 2, 2015

March 2, 2015

Posted by **Austin** on Thursday, December 27, 2012 at 7:15pm.

X^4+11x^3+24x^2-23x+35=0

Please show work

- calculus -
**Damon**, Thursday, December 27, 2012 at 7:28pmthe 35 tempts me to try -7 and -

divide mess by (x+5)

get

(x+5)(x^3+6x^2-6x+7)

so divide

(x^3+6x^2-6x+7) by (x+7)

get

(x+5)(x+7)(x^2-x+1)

now that last one has no real roots

b^2-4ac = 1-4 = -3

so our only real roots are

(-5,0) and (-7,0)

**Answer this Question**

**Related Questions**

calculus-can someone please help me with this ques - I have two questions if ...

college algebra--need help please!! - solve the equation in the real number ...

Math - Real number system - Solve the following equation in the real number ...

Discrete Math - Please help with this problem. Thanks a/ Show that for any real ...

college algebra - Solve the following equation in the real number system. Please...

calculus - how to find all real zeros of "4x^5+8x^4-15x^3-23x^2+11x+15

pre calculus - solve the following equation in the complex number system Please ...

pre calculus - find the real zeros of f(x)=x^4+6x^3-11x^2-24x+28

Algebra - almost done with Algebra...help! 2 3x – 6(2x – 0.055) = 10x + 0.515 I ...

algebra - college - Solve using the elimination method. Show your work. If the ...