Posted by Austin on Thursday, December 27, 2012 at 7:15pm.
the 35 tempts me to try -7 and -
divide mess by (x+5)
get
(x+5)(x^3+6x^2-6x+7)
so divide
(x^3+6x^2-6x+7) by (x+7)
get
(x+5)(x+7)(x^2-x+1)
now that last one has no real roots
b^2-4ac = 1-4 = -3
so our only real roots are
(-5,0) and (-7,0)
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