Posted by Austin on Thursday, December 27, 2012 at 7:15pm.
Solve the equation in the real number system
Please show work
calculus - Damon, Thursday, December 27, 2012 at 7:28pm
the 35 tempts me to try -7 and -
divide mess by (x+5)
(x^3+6x^2-6x+7) by (x+7)
now that last one has no real roots
b^2-4ac = 1-4 = -3
so our only real roots are
(-5,0) and (-7,0)
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