Posted by allisonPlease help!! on Thursday, December 27, 2012 at 5:08pm.
Find all zeros of the following polynomial. Write the polynomial in factored form. f(x)=x^33x^2+16x48
I put: x^2(x3)+16(x=3)
(x3)(x^2+16)
For zeros:
x3=0
x=0
**My teacher stated check the equation solution again. What is the value for x and hence what is the zero for the polynomial based on the first factor?
**Can someone help me?

calculuscan someone please help me with this ques  drwls, Thursday, December 27, 2012 at 6:09pm
You factored the cubic polynomial correctly as
(x3)(x^2 + 16)
The first term tells the function has a zero at x = 3.
The other roots are imaginary. x = +/ 4i

calculuscan someone please help me with this ques  allisonPlease help!!, Thursday, December 27, 2012 at 6:56pm
yes, I did put:
x^2+16=0
x^2= 16
x= + or 4i
But she wrote that on the first part that I submitted and I don't really know what it is that she wants me to do.
**So are you saying that the value for x is 3, but then what is the zero for the polynomial based on the first factor??

calculuscan someone please help me with this ques  Damon, Thursday, December 27, 2012 at 7:33pm
x3 = 0
means x = 0
so the polynomial is zero at x = 3
also at  4 i and at + 4 i
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