Posted by Paul on .
Solve the inequality. x^3+9x^2108 less than or equal to 0.
Then write in interval noation.
Please can you show me step by step on how you got the answer. I have tries and I am very confused.

calculusplease help!! 
Damon,
first this software is very handy for polynomials and seeing their graphs:
http://mathportal.org/calculators/polynomialssolvers/polynomialgraphingcalculator.php 
calculusplease help!! 
Damon,
(x+6)(x+6)(x3)
so we have double zero at x = 6 (graph comes up from way low and bounces back down off the x axis)
Then it comes back up again and goes positive at x = 3
SO
x^3+9x^2 108 </= 0 for
x<+3