Monday

April 21, 2014

April 21, 2014

Posted by **Anonymous** on Thursday, December 27, 2012 at 11:27am.

mean of cubes of first n natural numbers is [n(n+1)(n+1)]/4

- airthmetic progression -
**Steve**, Thursday, December 27, 2012 at 12:02pmby induction, you can show that

n

∑ k^3 = n^2 * (n+1)^2 / 4

k=1

now divide by n, and you're done.

**Related Questions**

maths-Arithmetic progression - Prove that mean of squares of first n natural ...

airthmetic progression - If m, n are natural numbers, m > n, sum of mth and ...

airthmetic progression - If m, n are natural numbers, m > n, sum of mth and ...

Geometric progression - The second term of a geometric progression is 12 more ...

Maths - 1..The first 2 terms of a geometric progression are the same as the ...

arithmetic - Two arithmetic progression have thd same first and last terms.the ...

Math (Geometric Progression) - 5 distinct positive reals form an arithmetic ...

GP Caluculus - The third term of a geometric progression is 16. The sum of the ...

GP Caluculus - The third term of a geometric progression is 16. The sum of the ...

GP Caluculus - The third term of a geometric progression is 16. The sum of the ...