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December 18, 2014

December 18, 2014

Posted by **Anonymous** on Thursday, December 27, 2012 at 11:26am.

mean of squares of first n natural numbers is (n+1)(2n+1)/6

- maths-Arithmetic progression -
**Steve**, Thursday, December 27, 2012 at 12:01pmyou will recall that

n

∑ k^2 = n(n+1)(2n+1)/6

k=1

it's pretty obvious then what the average is

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