two poles 15 meter and 30 meter high stand upright in a playground if their feet are 36 meter apart find the distance between their tops.

d^2 = 36^2 + (30-15)^2 = 36^2 + 15^2

d = 39

the tops form the hypotenuse of a 5-12-13 right triangle (scaled by 3)

ADD THE DISTANCE BETWEEN THE HEIGHT OF THE POLE AND 36

ANSWER=41M

To find the distance between the tops of two poles, we can use the Pythagorean theorem.

According to the problem, we have two poles with heights of 15 meters and 30 meters, respectively. The distance between their feet is given as 36 meters.

Let's denote the distance between the tops of the poles as 'd'.

We can form a right triangle with the two poles as the vertical sides and the distance between their feet as the base. The distance between the tops of the poles, 'd,' is then the hypotenuse of this right triangle.

Using the Pythagorean theorem, we have:

d^2 = (15)^2 + (30)^2

Simplifying this equation:

d^2 = 225 + 900
d^2 = 1125

To find the value of 'd,' we take the square root of both sides:

d = √(1125)
d ≈ 33.54 meters

Therefore, the distance between the tops of the two poles is approximately 33.54 meters.