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December 18, 2014

December 18, 2014

Posted by **phyllys** on Wednesday, December 26, 2012 at 9:33pm.

f(x)= x^4+3x^2-40

- Pre-Cal. -
**drwls**, Thursday, December 27, 2012 at 4:43amLet x^2 = y

y^2 +3y -40 = 0

(y+8)(y-5) = 0

y = -8 or 5

x = sqrty = +/- isqrt8 or +/- sqrt5

f(x) = (x - sqrt5)(x + sqrt5)(x^2 +8)

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