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December 20, 2014

December 20, 2014

Posted by **Anonymous** on Wednesday, December 26, 2012 at 7:40pm.

2) A new skateboarder's ramp just arrived at Bungey's Family Fun Center. A cross -sectional view shows that the shape is parabolic. The sides are 12 ft high and 15 ft apart. Write an equation that, when graphed, will show the cross section of this ramp.

- Algebra 2 .. -
**MathMate**, Wednesday, December 26, 2012 at 8:04pmBoth problems require to graph the vertex.

1. we know that the parabola passes through the following points: (0,0), (50,125),(100,0).

Using the standard formula, where (h,k) represent the coordinates of the vertex, we have h=50, k=125, and the parabola is:

y=a(x-h)^2+k=a(x-50)^2+125

Since the parabola passes through (0,0), we have

0=a(0-h)^2+k = ah^2+k = 2500a+125

=> a=-125/2500=-1/20

So parabola is

y=-(x-50)^2/20+125

(2) can be solved similarly.

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