Posted by **Anonymous** on Monday, December 24, 2012 at 10:43am.

In a pentagon ABCDE, angle B = 168, angle C:angleD = 23:25 and AB//ED. Find angle C and angle D.

- maths --plse help me.. -
**Steve**, Tuesday, December 25, 2012 at 5:07pm
since AB║DE, adding exterior angles at B,C,D = 180

(180-B)+(180-C)+(180-D) = 180

∠B+∠C+∠D = 360

168 + 23x + 25x = 360

48x = 192

x = 4

∠C = 92

∠D = 100

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