Posted by **Anonymous** on Monday, December 24, 2012 at 10:43am.

In a pentagon ABCDE, angle B = 168, angle C:angleD = 23:25 and AB//ED. Find angle C and angle D.

- maths --plse help me.. -
**Steve**, Tuesday, December 25, 2012 at 5:07pm
since AB║DE, adding exterior angles at B,C,D = 180

(180-B)+(180-C)+(180-D) = 180

∠B+∠C+∠D = 360

168 + 23x + 25x = 360

48x = 192

x = 4

∠C = 92

∠D = 100

## Answer This Question

## Related Questions

- maths - The convex pentagon ABCDE has a right angle at B,AB=BC andCD=DE=EA=1cm,...
- maths - In triangle ABC angle B > angle C if AM is the bisector of angle BAC...
- geometry - In a triangle ABC,right angled at B, BD is drawn perpendicular to AC...
- math - In a triangle ABC,right angled at B, BD is drawn perpendicular to AC. ...
- MATHS - In a triangle ABC, angle B> angle C. If AM is the bisector of angle A...
- maths - ABCD is a parallelogram the angle bisector of angleA and angleD ...
- MATHS - ABCD is a cyclic quadrilateral in which angle BAD=70,angle ADC=80 and ...
- geometry - obtuse triangle ABC with obtuse angle B. Point D on side AC such that...
- Geometry - Two lines intersect so that angle 1 and angle 3 are vertical angles, ...
- geometry - I need help on this homework question KL and KJ are opposites rays....

More Related Questions