Posted by Anonymous on Monday, December 24, 2012 at 10:43am.
In a pentagon ABCDE, angle B = 168, angle C:angleD = 23:25 and AB//ED. Find angle C and angle D.

maths plse help me..  Steve, Tuesday, December 25, 2012 at 5:07pm
since AB║DE, adding exterior angles at B,C,D = 180
(180B)+(180C)+(180D) = 180
∠B+∠C+∠D = 360
168 + 23x + 25x = 360
48x = 192
x = 4
∠C = 92
∠D = 100
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